Leaked source code of windows server 2003
You can not select more than 25 topics
Topics must start with a letter or number, can include dashes ('-') and can be up to 35 characters long.
|
|
/***
*strtokex.c - tokenize a string with given delimiters * * Copyright (c) 1989-1993, Microsoft Corporation. All rights reserved. * *Purpose: * defines strtok() - breaks string into series of token * via repeated calls. * *******************************************************************************/ #if defined(unix)
#define __cdecl
#endif
#include <windows.h>
#include <string.h>
/***
*char *StrTokEx(pstring, control) - tokenize string with delimiter in control * *Purpose: * StrTokEx considers the string to consist of a sequence of zero or more * text tokens separated by spans of one or more control chars. the first * call, with string specified, returns a pointer to the first char of the * first token, and will write a null char into pstring immediately * following the returned token. when no tokens remain * in pstring a NULL pointer is returned. remember the control chars with a * bit map, one bit per ascii char. the null char is always a control char. * *Entry: * char **pstring - ptr to ptr to string to tokenize * char *control - string of characters to use as delimiters * *Exit: * returns pointer to first token in string, * returns NULL when no more tokens remain. * pstring points to the beginning of the next token. * *WARNING!!! * upon exit, the first delimiter in the input string will be replaced with '\0' * *******************************************************************************/ char * __cdecl StrTokEx (char ** pstring, const char * control) { unsigned char *psz; const unsigned char *pszCtrl = (const unsigned char *)control; unsigned char map[32] = {0}; LPSTR pszToken; if(*pstring == NULL) return NULL; /* Set bits in delimiter table */ do { map[*pszCtrl >> 3] |= (1 << (*pszCtrl & 7)); } while (*pszCtrl++); /* Initialize str. */ psz = (unsigned char*)*pstring; /* Find beginning of token (skip over leading delimiters). Note that
* there is no token if this loop sets str to point to the terminal * null (*str == '\0') */ while ((map[*psz >> 3] & (1 << (*psz & 7))) && *psz) psz++; pszToken = (LPSTR)psz; /* Find the end of the token. If it is not the end of the string,
* put a null there. */ for (; *psz ; psz++) { if (map[*psz >> 3] & (1 << (*psz & 7))) { *psz++ = '\0'; break; } } /* string now points to beginning of next token */ *pstring = (LPSTR)psz; /* Determine if a token has been found. */ if (pszToken == (LPSTR)psz) return NULL; else return pszToken; }
|