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309 lines
6.1 KiB
309 lines
6.1 KiB
page ,132
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title ldsplit - split long double
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;***
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;ldsplit.asm - split long double into two doubles
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;
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; Copyright (c) 1992-2001, Microsoft Corporation. All rights reserved.
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;
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;Purpose:
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; Helper for handling 10byte long double quantities if there is no
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; compiler support.
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;
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;Revision History:
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;
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; 04/21/92 GDP written
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;
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;*******************************************************************************
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.xlist
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include cruntime.inc
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include mrt386.inc
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include elem87.inc
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include os2supp.inc
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.list
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.data
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labelB TagTable
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; C2 C1 C0 C3 Meaning
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db 2 * 4 ; 0 0 0 0 +Unnormal=> NAN
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db 1 * 4 ; 0 0 0 1 +Zero => Zero
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db 2 * 4 ; 0 0 1 0 +NAN => NAN
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db 2 * 4 ; 0 0 1 1 Empty => NAN
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db 2 * 4 ; 0 1 0 0 -Unnormal=> NAN
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db 1 * 4 ; 0 1 0 1 -Zero => Zero
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db 2 * 4 ; 0 1 1 0 -NAN => NAN
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db 2 * 4 ; 0 1 1 1 Empty => NAN
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db 0 * 4 ; 1 0 0 0 +Normal => Valid
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db 4 * 4 ; 1 0 0 1 +Denormal=> Denormal
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db 3 * 4 ; 1 0 1 0 +Infinity=> Infinity
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db 2 * 4 ; 1 0 1 1 Empty => NAN
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db 0 * 4 ; 1 1 0 0 -Normal => Valid
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db 4 * 4 ; 1 1 0 1 -Denormal=> Zero
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db 3 * 4 ; 1 1 1 0 -Infinity=> Infinity
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db 2 * 4 ; 1 1 1 1 Empty => NAN
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; factor = 2^64
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staticQ factor, 043F0000000000000R
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LDBIAS equ 3fffh
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DBIAS equ 3ffh
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MAX_BIASED_DEXP equ 7feh
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CODESEG
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table:
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dd valid
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dd zero
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dd nan
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dd inf
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dd denorm
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;***
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;int _ldsplit(pld, pd1, pd2) - split long double
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;
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;Purpose:
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; partition a long double quantity ld into two double quantities
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; d1, d2 and an integer scaling factror s. The mantissa of d1 has
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; the high order word of the mantissa of ld. Respectively, the
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; mantissa of d2 has the low order word of the mantissa of ld.
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; The following relation should be satisfied:
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;
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; ld == ((long double)d1 + (long double)d2) * 2^s
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;
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; s is 0, unless d1 or d2 cannot be expressed as normalized
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; doubles; in that case s != 0, and .5 <= d1 < 1
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;
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;
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;Entry:
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; pld pointer to the long double argument
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; pd1 pointer to d1
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; pd2 pointer to d2
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;
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;Exit:
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; *pd1, *pd2 are updated
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; return value is equal to s
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;
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;
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;Exceptions:
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; This function should raise no IEEE exceptions.
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; special cases:
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; ld is QNAN or SNAN: d1 = QNAN, d2 = 0, s = 0
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; ls is INF: d1 = INF, d2 = 0, s = 0
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;
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;
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;******************************************************************************/
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_ldsplit proc uses ebx edx edi, pld:dword, pd1:dword, pd2:dword
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local ld:tbyte
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local exp_adj:dword
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local retvalue:dword
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local denorm_adj:dword
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mov [retvalue], 0 ; default return value
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mov [denorm_adj], 0
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mov ebx, [pld]
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fld tbyte ptr [ebx]
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fxam
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fstsw ax
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fstp [ld] ; store to local area
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shl ah, 1
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sar ah, 1
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rol ah, 1
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and ah, 0fh
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mov al, ah
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mov ebx, dataoffset TagTable ; Prepare for XLAT
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xlat
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movzx eax, al
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mov ebx, OFFSET table
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add ebx, eax
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mov edx, pd1 ; edx points to the high order double
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mov edi, pd2 ; edi points to the low order double
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jmp [ebx]
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lab valid
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; have a valid normalized non-special long double
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mov eax, dword ptr [ld]
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or eax, eax
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jz d2zero
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; compute mantissa an exponent for d2
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mov [exp_adj], 31 ; adjustment to be subtracted from exp of *pd2
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;
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; compute mantissa of d2
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; shift left low order word of ld, until a '1' is hit
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;
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cmp eax, 0ffffh
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ja shl16done
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sal eax, 16
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add [exp_adj], 16
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lab shl16done
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cmp eax, 0ffffffh
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ja shl8done
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sal eax, 8
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add [exp_adj], 8
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lab shl8done
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lab shiftloop
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inc [exp_adj]
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sal eax, 1
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jnc shiftloop
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; now eax contains the mantissa for d2
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; exp_adj is the difference of the
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; exponents of d1 and d2
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; exp_adj should be in the range
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; 32 <= exp_adj <= 63
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; By convention, if exp_adj is 0 then
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; d2 is zero
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lab setd2man
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mov dword ptr [edi+4], 0
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shld dword ptr [edi+4], eax, 20
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shl eax, 20
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mov [edi], eax
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;
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; set mantissa of d1
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;
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lab setd1man
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mov eax, dword ptr [ld+4]
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sal eax, 1 ; get rid of explicit bit
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mov dword ptr [edx+4], 0
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shld dword ptr [edx+4], eax, 20
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shl eax, 20
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mov [edx], eax
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; check if exponent is in range
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mov ax, word ptr [ld+8]
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and ax, 07fffh ; clear sign bit
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movzx eax, ax
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sub eax, LDBIAS - DBIAS
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cmp eax, MAX_BIASED_DEXP
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ja expoutofrange
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cmp eax, [exp_adj]
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jb expoutofrange
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;
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; set exponent of d1
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;
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lab setexp1
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mov ebx, eax ; save exp value
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shl eax, 20
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or dword ptr [edx+4], eax
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cmp [exp_adj], 0
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je exp2zero
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sub ebx, [exp_adj]
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je exp2zero
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lab setexp2
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shl ebx, 20
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or dword ptr [edi+4], ebx
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mov [retvalue], 0
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lab setsign ; set correct signs and return
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; at this point eax contains
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; the return value
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mov bx, word ptr [ld+8]
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and bx, 1 SHL 15 ; get sign
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or [edi+6], bx ; set sign bit
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or [edx+6], bx ; set sign bit
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mov eax, [retvalue]
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add eax, [denorm_adj]
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ret
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lab d2zero
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mov [exp_adj], 0
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jmp setd2man
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lab exp2zero
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mov ebx, 0
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jmp setexp2
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lab expoutofrange
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mov ebx, DBIAS
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mov ecx, ebx
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sub ecx, [exp_adj]
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shl ebx, 20
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or dword ptr [edx+4], ebx
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shl ecx, 20
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or dword ptr [edi+4], ecx
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sub eax, DBIAS ; unbias exp
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mov [retvalue], eax ; this is the return value
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jmp short setsign
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lab zero
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mov dword ptr [edx], 0
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mov dword ptr [edx+4], 0
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mov dword ptr [edi], 0
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mov dword ptr [edi+4], 0
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jmp setsign
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lab nan
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mov dword ptr [edx], 0
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mov dword ptr [edx+4], 07ff80000h
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mov dword ptr [edi], 0
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mov dword ptr [edi+4], 0
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jmp setsign
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lab inf
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mov dword ptr [edx], 0
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mov dword ptr [edx+4], 07ff00000h
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mov dword ptr [edi], 0
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mov dword ptr [edi+4], 0
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jmp setsign
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lab denorm
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;
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; We have a long double denormal
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; so we know for sure that this is out of the double
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; precision range, and the return value of _ldsplit
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; should be non-zero.
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; Multiply the denormal by 2^64, then adjust the
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; return value by subtracting 64
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;
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; this assumes denormal exception masked
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fld [ld]
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fmul [factor]
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fstp [ld]
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mov [denorm_adj], 64
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jmp valid
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_ldsplit endp
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end
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