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title ulldiv - unsigned long divide routine ;*** ;ulldiv.asm - unsigned long divide routine ; ; Copyright (c) 1985-1994, Microsoft Corporation. All rights reserved. ; ;Purpose: ; defines the unsigned long divide routine ; __aulldiv ; ;*******************************************************************************
.xlist include cruntime.inc include mm.inc .list
;*** ;ulldiv - unsigned long divide ; ;Purpose: ; Does a unsigned long divide of the arguments. Arguments are ; not changed. ; ;Entry: ; Arguments are passed on the stack: ; 1st pushed: divisor (QWORD) ; 2nd pushed: dividend (QWORD) ; ;Exit: ; EDX:EAX contains the quotient (dividend/divisor) ; NOTE: this routine removes the parameters from the stack. ; ;Uses: ; ECX ; ;Exceptions: ; ;*******************************************************************************
CODESEG
_aulldiv PROC NEAR
push ebx push esi
; Set up the local stack and save the index registers. When this is done ; the stack frame will look as follows (assuming that the expression a/b will ; generate a call to uldiv(a, b)): ; ; ----------------- ; | | ; |---------------| ; | | ; |--divisor (b)--| ; | | ; |---------------| ; | | ; |--dividend (a)-| ; | | ; |---------------| ; | return addr** | ; |---------------| ; | EBX | ; |---------------| ; ESP---->| ESI | ; ----------------- ;
DVND equ [esp + 12] ; stack address of dividend (a) DVSR equ [esp + 20] ; stack address of divisor (b)
; ; Now do the divide. First look to see if the divisor is less than 4194304K. ; If so, then we can use a simple algorithm with word divides, otherwise ; things get a little more complex. ;
mov eax,HIWORD(DVSR) ; check to see if divisor < 4194304K or eax,eax jnz short L1 ; nope, gotta do this the hard way mov ecx,LOWORD(DVSR) ; load divisor mov eax,HIWORD(DVND) ; load high word of dividend xor edx,edx div ecx ; get high order bits of quotient mov ebx,eax ; save high bits of quotient mov eax,LOWORD(DVND) ; edx:eax <- remainder:lo word of dividend div ecx ; get low order bits of quotient mov edx,ebx ; edx:eax <- quotient hi:quotient lo jmp short L2 ; restore stack and return
; ; Here we do it the hard way. Remember, eax contains DVSRHI ;
L1: mov ecx,eax ; ecx:ebx <- divisor mov ebx,LOWORD(DVSR) mov edx,HIWORD(DVND) ; edx:eax <- dividend mov eax,LOWORD(DVND) L3: shr ecx,1 ; shift divisor right one bit; hi bit <- 0 rcr ebx,1 shr edx,1 ; shift dividend right one bit; hi bit <- 0 rcr eax,1 or ecx,ecx jnz short L3 ; loop until divisor < 4194304K div ebx ; now divide, ignore remainder mov esi,eax ; save quotient
; ; We may be off by one, so to check, we will multiply the quotient ; by the divisor and check the result against the orignal dividend ; Note that we must also check for overflow, which can occur if the ; dividend is close to 2**64 and the quotient is off by 1. ;
mul dword ptr HIWORD(DVSR) ; QUOT * HIWORD(DVSR) mov ecx,eax mov eax,LOWORD(DVSR) mul esi ; QUOT * LOWORD(DVSR) add edx,ecx ; EDX:EAX = QUOT * DVSR jc short L4 ; carry means Quotient is off by 1
; ; do long compare here between original dividend and the result of the ; multiply in edx:eax. If original is larger or equal, we are ok, otherwise ; subtract one (1) from the quotient. ;
cmp edx,HIWORD(DVND) ; compare hi words of result and original ja short L4 ; if result > original, do subtract jb short L5 ; if result < original, we are ok cmp eax,LOWORD(DVND) ; hi words are equal, compare lo words jbe short L5 ; if less or equal we are ok, else subtract L4: dec esi ; subtract 1 from quotient L5: xor edx,edx ; edx:eax <- quotient mov eax,esi
; ; Just the cleanup left to do. edx:eax contains the quotient. ; Restore the saved registers and return. ;
L2:
pop esi pop ebx
ret 16
_aulldiv ENDP
end
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